25 ml of H2 and 18ml of I2 vapours were heated in a sealed vessel at 456 C when at - Chemistry - Chemical and Ionic Equilibrium

Question

25 ml of H2 and 18ml of I2 vapours were heated in a sealed vessel
at 456 C when at equilibrium 30 8 ml of HI was formed Calculate the
degree of dissociation of pure HI

Rahul Yogi · Accepted Answer

Dear student,

The degree of dissociation of HI can be calculated from the
reaction,

H2 + I2→2HI
Clearly, I2 is the limiting reagent hence the amount of
HI formed depends on volume of I2
1 mL of I2 will produce 2 mL of HI, hence 18mL of
I2 will produce 36 mL HI theoretically
Volume of HI formed theoretically = 36 mL
â€‹Volume of HI formed actually = 30 8 mL

Degree of dissociation = 30 836×100 = 85 55%
Hope this helps,
Regards

25 ml of H2 and 18ml of I2 vapours were heated in a sealed vessel at 456 C when at equilibrium 30.8 ml of HI was formed. Calculate the degree of dissociation of pure HI