# 27.A capacitor of 8 microfarad is charged to a potential of 1000V. The energy stored in the capacitor is

Please find below the solution to the asked query:

Given, C = 8μF= 8 X 10

^{-6}F.

V = 1000 volts

Energy stored in the capacitor is given by the expression :

$U=\frac{1}{2}C{V}^{2}=\frac{1}{2}\times 8\times {10}^{-6}\times {10}^{3}=4\times {10}^{-3}Joules.$

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