27.A capacitor of 8 microfarad is charged to a potential of 1000V. The energy stored in the capacitor is

Dear Student,
Please find below the solution to the asked query:
Given, C = 8μF= 8 X 10^-6 F.
V = 1000 volts
Energy stored in the capacitor is given by the expression :
$U =\frac{1}{2} C{V}^2 = \frac{1}{2} \times 8 \times {10}^{-6} \times {10}^3 = 4 \times {10}^{-3 }Joules.$

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