29) In the figure, AB and CD are two chords of a circle with centre O and MN as diameter. They intersect at point E. If ∠ A E N = ∠ D E N = 45 ° and AB = 6.5 cm, then the length of chord CD is equal to. ( a ) 13 c m ( b ) 6 . 5 c m ( c ) 7 . 0 c m ( d ) n o n e o f t h e s e Share with your friends Share 2 Manbar Singh answered this Draw OP⊥AB and OQ⊥CDIn ∆OPE and ∆OQE∠OPE = ∠OQE 90° each∠PEO = ∠QEO as, ∠AEN = ∠DEN = 45° EO = EO Common⇒∆OPE ≅ ∆OQE AAS⇒OP = OQ CPCTSo, chords AB and CD are equidistant from the centre.We know that chords that are equidistant from the centre are equal in length.So, AB = CD = 6.5 cm 2 View Full Answer Priyanshi Goyal answered this It will be equal to 6.5. 0 Pallavi Rathore answered this CD will be 6.5 by the theorem if the angle substended by 2 chords is equal than the chords are equal 0 Asmit answered this 6.5 according to theroem 0
