Dear Student
Volume Of the block = 4*10*20 = 800 cm3
Mass of the block m = volume * density = 800 * 7.5 = 6000 gm = 6 kg
Weight of the block W = mg = 6 * 10 = 60N
Thrust by the surface should be equal to the weight because it is at equilibrium so net force should be zero.
Therefore thrust in both the cases = 60N
Pressure exerted by the block P = Thrust / face area
Maximum pressure Pmax = W/Amin = 60/(4*10*10-4) = 15000 Pa
Minimum Pressure PMin = W/Amax = 60/(20*10*10-4) = 3000 Pa
I hope the solution is helpful.
Keep asking question, keep learning.
Regards
Volume Of the block = 4*10*20 = 800 cm3
Mass of the block m = volume * density = 800 * 7.5 = 6000 gm = 6 kg
Weight of the block W = mg = 6 * 10 = 60N
Thrust by the surface should be equal to the weight because it is at equilibrium so net force should be zero.
Therefore thrust in both the cases = 60N
Pressure exerted by the block P = Thrust / face area
Maximum pressure Pmax = W/Amin = 60/(4*10*10-4) = 15000 Pa
Minimum Pressure PMin = W/Amax = 60/(20*10*10-4) = 3000 Pa
I hope the solution is helpful.
Keep asking question, keep learning.
Regards