300 Joules of work is done in sliding a 2 kg block up a inclined plane of height 10 m. What is the work done against the force of friction?
Experts please answer!

 

Work done against gravity = mg sin q × d

 

        = 2 × 10 × 10    (d sinq = 10)

 

= 200 J

 

Actual work done = 300 J

 

Work done against friction = 300 - 200 = 100 J

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