33 33 A car accelerates from rest at a constant rate α for some time, after which - Science - Electricity

Question

33

33 A car accelerates from rest at a
constant rate α for some time, after which deaccelerates as a
constant rate β to come to rest If the total time elapsed is
1, the maximum velocity accquired to the car is given by

( A )   α β /   α   +   β
t                  
                 
                 
        ( B )   α   +  
β   / α β t   ( C )   α 2
  +   β 2 /   α β t    
                 
                 
              ( D )  
α 2   -   β 2 /   α β t

Decoder_2 · Accepted Answer

Dear student,
Here i am taking a and b in place of
α and β

u = 0

a 1 = a

t = t s

a 2 = b

Let the maximum velocity attained be v at time t1

Thus

v = u + a t1

=> v = at1 ---1

vf = 0 after t – t1 seconds @ b ms
-2 retardation

Thus

0 = v – b(t-t1)

By 1

=> at1 – b(t-t1) = 0

=> t1(a + b) = bt

=> t1 = bt/(a+b)

Again,

v = at1

=> v = {ab/(a+b)}t
so the final answer will be,

αβα+βt
Regards