378 multiply by 497. what is very easy method to solve this problem????

187866

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what method to slove the problem of 378 multiply by 497

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  This method is a little difficult to understand but you 'll get  used to it . It can give you results faster.

READ CAREFULLY . DON'T CONFUSE YOURSELF

I will use a different question so that you can understand easily:    142                                                                                                                                                                                                         X 563    

                           

First, multiply 3 and 2 (unit digits) .ie. 3 X 2 = 6.Therefore, 6 is the unit digit of answer.

The next step is 3 X 4 + 2 X 6 = 24 where 4 is the second digit of answer and 2 is the balance.

Then 1 X 3 + 2 X 5 + 4 X 6 = 37.Add the balance mentioned above ie 37 + 2 = 39.  9 is the third digit of answer and 3 the balance.

The next step is 4 X 5 + 1 X 6 = 26. Adding the balance, you get 26 + 3 = 29 where 9 is the fourth digit of answer and 2 the balance.

The last step is to multiply 1 and 5 ie. 1 X 5 = 5 and add the balance -  5 + 2 = 7 where 7 is the last digit of answer .

So, the ANSWER is  79946.

You can apply the same method to the question you asked.

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378
497

First multiply the numbers in unit's place. (8*7) = 56

Then, multiply the ten's place of the first number
with the unit's place of the second number and unit place of first number
with ten's place of second number and add them. [(7*7) + (8*9)] = 49 + 72 = 121

Next, multiply the hundred's place of the first number with the one's place of the second number
and one's place of the first number with the hundred's place of the second number. Add
the products. Then multiply the ten's values of both the numbers. Add this to the sum of the previous
two products.
(3*7) + (8*4) + (7*9) = 21 + 32 + 63 = 116.

Next, multiply the tens digit of the first number with the digit in  hundred place of the second number  and
multiply the hundred's digit of the first number with the ten's place of the second number and add them.
(3*9) + (4*7) = 27 + 28 = 55

Finally, multiply the hundred's place of both the numbers.
4*3 = 12

You will have 6 numbers now. Write them in the reverse order of steps

i.e - 12 55 116 121 56

From here it's fairly simple.
Start from the last digit,
Write 6  ---> 6 in unit's place
Then, 5+1  = 6  ----> 6 in ten's place
Then, 12 + 6 = 18 ---->  8 in hundred's place with 1 carried
Then, 11 + 5 = 16 + 1 = 17 (which you carried)--> 7 in thousand's place with carried (again because it's 17)
Then, 5 + 2 = 7 + 1 = 8 ----> 8 in ten thousand's place
Finally. write the first number which is 1 ---> 1 in hundred thousand's place.

There you have your answer, 187866

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The answer would surely be 187866

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May these be helpful

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