3sinx + 4cosx = 5 show tan x = 3/4

Given 3sinx +4cos x = 5divide by cos x we get, 3sinxcos x +4 = 5cos x3tanx +4= 5secx Now squaring we get, 9tan2x+16+24tanx =25sec2x9tan2x+16+24tanx =25+25tan2x16tan2x-24tanx+9=0 4tanx -32=0tan x = 34

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multiply and divide the eq. by 5

5(3/5 sinx + 4/5 cosx)

5(sinx.cos53 + cosx.sin53)

5 sin(x+53) = 5

so x+53 = 90

x=37

tan37 = 3/4

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