4.8g of O2 was used to burn 0.15 moles of Fe to Fe2O3. What mass of Fe2O3 was formed? Share with your friends Share 1 Yasodharan answered this Dear Student, The computation are expressed below, 4.8 g O2=4.832=0.15 mol0.15 mol O2 produces product =2×0.15=0.3 mol Fe2O3mass of Fe2O3=159.692 gmol×0.3 mol = 47.9076 gm Regards. -23 View Full Answer