41) A 60 cm long wire ( mass 10 g ) is hanged by two flexible wires in a magnetic field of 0.40 T. Find the magnitude and direction of the current required to be flown to neutralize the tension hanging wires.


Answer : 0.41 A, from left to right.

Dear Student ,
Here in this case from the given data we can write that ,
F=BILmg=BILI=mgBL=10×10-3×100.4×60×10-2=0.41 A
The current is flowing from left to right .
Regards

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