let 1st set of nos be a1=k, a2=k+1, ..k+4,
so avg= 5k+10/5= k+2
Similarly, let 2nd ser of numbers be
b1=h, b2=h+1,...b5=h+4
so avg= 5h+10/5= h+2.
But k+2=2+h-2 (as given in qu.), Hence h=k+2,
So, 2nd set of nos are= k+2,k+3,k+4,k+5, k+6
Whereas 1st set (a1,a2...a5)was k,k+1,k+2,k+3,k+4
So COMMON NOS IN BOTH SETS are 3 numbers (,i e k+2,k+3,k+4)
