5.82gm of silver coin was dissolved in strong nitric acid and excess sodium chloride was added.the silver chloride precipitate were dried and weighed 7.2gm. calculate % of silver in the coin.

Dear student

Ag+ 2HNO3  AgNO3 + NO2 + H2OAgNO3 + NaCl AgCl + NaNO3143.5g of silver chloride would be precipitated by 108g of silveror 1g will be precipitated by 108/143.5g 7.2g will be precipitated by 108/143.5 x 7.2= 5.4gi.e 5.82g contains 5.4g pure silver100g will contain: 5.4/5.82×100%= 92.7%
Regards

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