500g of water at 80 c is mixed with 250g of water at 50c . calculate the final temperature of the mixture?

Let the final temperature of the mixture be x

For 500 g of water,

m = 500g , t = (80 - x) C (since both the substances are water we don't require the specific heat capacity)

So, Q = 500 x (80 - x) J

For 250 g of water,

m = 250g , t = (x - 50) C

So, Q = 250 x (x - 50) J

According to the principle of calorimetry,

heat gained = heat lost

= 500 x (80 - x) = 250 x (x - 50)

After solving, we get, x= 70

Therefore the final temperature of the mixture = 70 ⁰ C