5g of NaCl is dissolved in 1000g of water. If the density of the resulting solution is 0.997 g/cm3, find the molarity and molality of solution.

molecular mass of NaCl=23*1+35.5*1
=58.5g/mol
molality=mass of solute*1000/molecular mass*mass of solvent(in g)
=5*1000/58.5*1000
.0854m
weight of solution=weight of solvent+weight of solute
=1000+5
=1005g
1 liter=1000ml=1cm cube
density=mass/volume
.997=1005/volume
volume=1005/.997
=1008.02 l
molarity=mass of solute in g/molecular mass*volume of solution in l
=5/58.5*1008.02
=5/58969.17
=8.479M
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5g of NaCl dissolve in 1000g of H2o . if the density of resulting solution is 0.997cm3 , calculate mole fraction of solute
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