68) A body of mass 4 kg is rotating in a vertical circle at the end of a string of length 0.6 m . calculate the difference of K.E at the top and the bottom of the circle.
Dear student,
When a body goes from bottom to top, its height becomes 2r.
Kinetic energy at the bottom is consumed in doing work against gravity = mg(2r)
And the remaining kinetic energy at top becomes
KE (top) = KE (bottom) - 2mgr
Hence,
KE (top) - KE (bottom) = 2mgr
Hope your doubts are cleared. In case of further queries, please post again.
Regards
When a body goes from bottom to top, its height becomes 2r.
Kinetic energy at the bottom is consumed in doing work against gravity = mg(2r)
And the remaining kinetic energy at top becomes
KE (top) = KE (bottom) - 2mgr
Hence,
KE (top) - KE (bottom) = 2mgr
Hope your doubts are cleared. In case of further queries, please post again.
Regards