9) In the given figure, O is the centre and AOC is a diameter of the circle . Find


(i) the sum of the areas of the two shaded segments made by the chords AB and BC.
(ii) the area of the shaded segment made by the chord PQ. t a k e , π = 22 7

Dear student,

In ABC,AC2=AB2+BC2AC2=42+42AC2=16+16=32AC=42cmthus, OA=OC=42cm2=22cmOB =OA=OC each radius of circlethus OB=22cm area of triangle =12×42×22=8cmNow, area of semi circle=πr22 =227×2×22×22=887cm2=12.5cm2thus, area of shaded portion =area of semicircle -area of triangle=12.5-8=4.5cm2hence, the sum of the area of two shaded segments made by chord AB and BC=4.5cm2

Regards

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Area of semicircle-area of triangle
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