9) In the given figure, O is the centre and AOC is a diameter of the circle . Find (i) the sum of the areas of the two shaded segments made by the chords AB and BC. (ii) the area of the shaded segment made by the chord PQ. t a k e , π = 22 7 Share with your friends Share 18 Shruti Tyagi answered this Dear student, In △ABC,AC2=AB2+BC2AC2=42+42AC2=16+16=32AC=42cmthus, OA=OC=42cm2=22cmOB =OA=OC each radius of circlethus OB=22cm∴ area of triangle =12×42×22=8cmNow, area of semi circle=πr22 =227×2×22×22=887cm2=12.5cm2thus, area of shaded portion =area of semicircle -area of triangle=12.5-8=4.5cm2hence, the sum of the area of two shaded segments made by chord AB and BC=4.5cm2 Regards 15 View Full Answer Yashasvi Mehta answered this 1st part . Area of semicircle-area of triangle 2