9) photosensitive surface is receiving light of wavelength 5000 (angstrom) at the rate of 10^-7 J/sec find - Physics -

Question

9) photosensitive surface is receiving light of wavelength 5000 ?
(angstrom) at the rate of 10^-7 J/sec find the number of photons
recieved per second

Vijay Shankar Yadav · Accepted Answer

Dear Student,
energy of one photon =hcλ=6
64×10-34×3 0×1085000×10-10=3
98×10-19Jso no of photon recieving per second  =10-73
98×10-19=2 5×1011
Regard

9) photosensitive surface is receiving light of wavelength 5000 ? (angstrom) at the rate of 10^-7 J/sec. find the number of photons recieved per second