a 0.24g sample of compound of oxygen and boronwas found by analysis to contain 0.096g of boron and 0.144g of oxygen. calculate the percentage composition of the compound by weight.

Given,

Mass of boron = 0.096

Mass of Oxygen = 0.144

Total mass = 0.24

% of boron = 0.096*100/0.24

= 0.4 *100

0.01 * 100

= 40%

% of Oxygen = 0.144*100/0.24

= 0.6 *100

0.01 * 100

= 60%

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