A bag contains some cards which are numbered between 31 and 96 are
placed. If one card is drawn from the bag, find the probability that thenumber on card is :(i) a multiple of 3(ii) a perfect square(iii) a number not more than 40
Bag contain cards from 31 to 96
So
1) multiple of 3 in between 31 to 96 is ( 33 ,36,39 ,42,45,48,52,54,57,60,63,66,69,72,75,78,81,84,87,91,94)
So number of favourable event = 21
Hence the probability = 21/66 = 7/22
2) A perfect square is
( 36 , 49 , 64 ,81)
So probability = 4/66 =2/33
3)number not more than 40 is 31,32,33,34,35,36,37,38,39
So there are 9 numbers
hence the probability = 9/66 = 3/22
So
1) multiple of 3 in between 31 to 96 is ( 33 ,36,39 ,42,45,48,52,54,57,60,63,66,69,72,75,78,81,84,87,91,94)
So number of favourable event = 21
Hence the probability = 21/66 = 7/22
2) A perfect square is
( 36 , 49 , 64 ,81)
So probability = 4/66 =2/33
3)number not more than 40 is 31,32,33,34,35,36,37,38,39
So there are 9 numbers
hence the probability = 9/66 = 3/22