A bag contains some marbles. Half is given to A, one third of remaining to B and rest to C. If C has twice the number of marvels than B, how many marbels are there in all?

Answer :

Let bag contains total marbles  =  x

So, According to given information , Half is given to A

A has total marbles  = x2

Remaining marbles after given half to A  =  x  - x2  =  x2 

From remaining one third of remaining to B , So

B has total marbles  =  x2  × 13  =  x6


C has total marbles  =  x2 - x6  = 3x - x6  = x3 

And also given  C has twice the number of marbles than B , SO we get

  C has total marbles  =  2  (  B has total marbles )

x3  =  2 ( x6  )


So here we can't find how many balls in the bag , there is some information is missing ,

As we take x  =  30
A  =  15
B  =  5
C  =  10

Or if we take x  =  60
A  =  30
B  =  10
C  =  20

So value of total balls in bag could be anything as here we have relationship between number of balls with A , B and C ,

So Please recheck your question again and get back to us , so we can help you .

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