a ball is thrown from the top of the tower in vertically upward direction velocity at point h - Physics -

Question

a ball is thrown from the top of the tower in vertically upward
direction velocity at point h meter below the point of projection
is twice of the velocity at a point h meter above the point of
projection find the maximum height reached by the ball above the
top of tower

Vara · Accepted Answer

Letu=Velocity of projectionVelocity at a point h below the point of projection = 2 × Velocity at a point h above the point of projectionu2+2gh=2u2-2ghSquare on both sides:u2+2gh=2u2-2ghu2+2gh=2u2-4ghu2=6ghHence,Maximum height isH=u22g   =6gh2g   =3h

a ball is thrown from the top of the tower in vertically upward direction . velocity at point h meter below the point of projection is twice of the velocity at a point h meter above the point of projection. find the maximum height reached by the ball above the top of tower.