A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m/s. the ball reaches the ground after 5 sec.Calculate-

1- the height of the tower? TAKE 'g' = 9.8 m/sec square

2- The velocity of the ball reaching the ground.

given:

 v=0; u=19.6;t=5, but it reaches the ground after 5 sec but we have to calculate the ht. of the tower so tat is only half the journey. so t= 5/2=2.5. as vthe ball is being thrown upwards a= - 9.8.

  1) using s=ut +12at square

      put the value nd u'll get answer 18.38m

 i dnt no if the ans is correct.but if it is hope it helps