A balloon is ascending vertically with an acceleration of 0 2m/s2, Two stones are dropped from it at an interval - Science -

Question

A balloon is ascending vertically with an acceleration of 0 2m/s2,
Two stones are dropped from it at an interval of 2 sec Find the
distance between them 1 5 sec after the second stone is released
(use g=9 8m/s2)

Neha Gupta · Accepted Answer

distance travelled by the first stone in 2+1
5 = 3
5 secondsS1 = ut+12at2u = 0net acceleration in downward direction is aa = g-0
2 = 9 6 m/s2S1 = 12(9 6)(3
5)2for second stone, distance travelled in 1
5 secondsS2 = 12(9 6)(1 5)2S=S1-S2 =12 (9
6)(3 5)2-12(9 6)(1 5)2= 58 8-10 8 = 40 m

A balloon is ascending vertically with an acceleration of 0.2m/s2, Two stones are dropped from it at an interval of 2 sec. Find the distance between them 1.5 sec after the second stone is released.(use g=9.8m/s2)