A barrel of 50 Kg is raised up on a 10 mt long inclined plane, by an effort of 25 N. Calculate the vertical height, through which the barrel rises
Hi Ghosh, data given are not so related based on scientific sense.
If suppose 25 kg wt is the force enough to raise it then angle of inclination of the plane will be got from
50 kg wt sin @ = 25 kg wt
==> sin @ = 1/2
==> @ = 30 degree
Now 10 m is hypotenuse and h is the height. So sin 30 = h/10
OR 1/2 = h/10
==> vertical height = 5 m
Please avoid using "mt" for the unit metre. Just "m" would do
kg wt is the unit of force which equals to g N
If suppose 25 kg wt is the force enough to raise it then angle of inclination of the plane will be got from
50 kg wt sin @ = 25 kg wt
==> sin @ = 1/2
==> @ = 30 degree
Now 10 m is hypotenuse and h is the height. So sin 30 = h/10
OR 1/2 = h/10
==> vertical height = 5 m
Please avoid using "mt" for the unit metre. Just "m" would do
kg wt is the unit of force which equals to g N