a battery of 10V carries 20,000 C of charge through a resistance of 20 ohms. the work done in 10 secs is?

Workdone by current flowing through the resistor in time t=I2R t,  where i, r and t are current, resistance and time during which current flows through the circuit.Current through the circuit,  I=VR,  where V=10V, andR=20 ohm. Therefore,I=1020=0.5 A.  Now workdone by this current in 10 second,W=I2R t=0.52×20×10=0.25×200=50 J.

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