a beaker 20cm high filled with an oil of r i 1 4 and the upper half filled with water - Physics - Ray optics Optical instrument

Question

a beaker 20cm high filled with an oil of r i 1 4 and the upper
half filled with water of r i 1 33 what is apparent depth of the
beaker as observed normally?

Jyoti Pant · Accepted Answer

Here,Shift due to water=Dw=[1-1n]×d=[1-11
33]×10Similarly,Shift due to oil=Do=[1-11 4]×10Total
shift=Dw+Do=[1-11 33]×10 +[1-11 4]×10Apparent
depth=Total height of beaker-Total shift=20-{[1-11 33]×10
+[1-11 4]×10}=14 6 cm

a beaker 20cm high filled with an oil of r.i 1.4 and the upper half filled with water of r.i 1.33 what is apparent depth of the beaker as observed normally?