a body A of mass 3 kg and a body B of mass 10 kg are dropped simultaneously from a height of 14.9 m .calculate:(A) their momenta(B) their potential energy(C) their kinetic energywhen they are 10 m above the ground. Share with your friends Share 6 Vara answered this Velocity of A at the height of 10 m:v1=2gh1-h2 =2×9.8×14.9-10 =9.8 m/sVelocity of B at the height of 10 m:v2=2gh1-h2 =2×9.8×14.9-10 =9.8 m/s(a)Momentum of A:P1=m1v1 =3×9.8 =29.4 kg.m/sMomentum of B:P2=m2v2 =10×9.8 =98 kg.m/s(b)Potential energy of A:PEA=m1gh2 =3×9.8×10 =294 JPotential energy of B:PEB=m2gh2 =10×9.8×10 =980 J(c)Kinetic energy of A:KE1=12m1v12 =12×3×9.82 =144.1 JKinetic energy of B:KE2=12m2v22 =12×10×9.82 =480.2 J 0 View Full Answer