A body is dropped from a height of 320m. The acceleration due to gravity is 10m/s^2? (a) How long does it take to reach the ground? (b) What is the velocity with which it will strike the ground? Share with your friends Share 14 Jyoti Pant answered this Given, h=320 mg=10 m/s2u=0Using, v2-u2=2ghor v2-0=2×10×320=6400or v=80 m/sThis is the velocity with which the body will strike the ground.Again,v=u+gtor t=v-ug=80-010=8 secThus, (i) 8 sec(ii) 80 m/s 16 View Full Answer