A body is sliding down an inclined plane under its own weight at constant speed. If the inclination of the plane to the horizon is 30 ,what is the angle of friction

Dear student
As the block is moving with constant velocity on the plane so net force on it must be zero.mgsin30°=μmgcos30°μ=tan30°=13Angle of friction θ is the angle between force of friction and the normal when the block is on the verge of motion at which friction is limiting in nature.tanθ=μ×NN=μ=13θ=30°Regards

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