A body moving with a constant acceleration travels the distance 3m and 8m respectively in 1s and 2s. Calculate (i) the initial velocity and (ii) the acceleration of the body.

Answer:

(i) 2 m/s

(ii) 2 m/s^{2}

Use the formula

s = u * t + 0.5 * a * t^{2}

For s = 3 t = 1

We get

3 = u + 0.5 * a -- (1)

For s = 8 and t = 2

We get

8 = 2 * u + 0.5 * a * 4 -- (2 )

Solving ( 1 ) and ( 2 ), we get u = 2 m/s and a = 2 m/s^{2}

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