A body of mas 3 kg and a body of mass 10 kg are simultaneously dropped from a height of 14.9 m.Calculate their momenta,their potential energies and kinetic energies when they are 10 m above the ground. Please give the final answer also.ITS URGENT.
Let the oblect of mass 10 kg be A and the object of mass 3 kg be B
Formulae =
g = 9.8
P.E. = mgh
P (momentum) = mv
K.E. = mv2/ 2
v2 of both A & B (it does not depend on mass) = u2 + 2as
OK so P.E. of A =
10 kg * 10 m * 9.8 m/s2
= 980 joule
P.E. of B =
3 kg * 9.8 m/s2 *10 m
= 294 joule
v2 = 0 + 2 * 9.8 m/s2 * (14.9 - 10) m
v2 = 96.04 m/s = 96 m/s (rounded)
v = (root 96) m/s = 9.7979 m/s = 9.8 m/s (rounded)
K.E. of A =
10 kg * 96 m/s * 1/2
= 480 joule
K.E. of B =
3 kg * 96 m/s * 1/2
= 144 joule
P of A =
10 kg * 96 m/s
= 960 kg m/s
P of B =
3 kg * 9.8 m/s
= 29.4 kg m/s