a body starts from rest and moves with a uiform accelerationof 5m/s2 for 5s and then it moves witha constant - Science -

Question

a body starts from rest and moves with a uiform accelerationof
5m/s2 for 5s and then it moves witha constant velocity for 4s later
it slows down comes down to rest in 5s
a)what is the maximum velocity attended by the body?
bwhat is the distance travelled during this period of
acceleration ?
c)what is the distance travelled when the body was moving with
constant velocity?
d)what is the retardation of the body while slowing down?
e)what is the distance travelled by retarding
f)what is the total distance travelled?

Neha Gupta · Accepted Answer

Initial velocity u = 0a = 5 m/s2t = 5 sV = u +atv = 0+ 5×5v = 25 m/ss1 =ut + 12at2s1 = 0 +12×5×5×5s1 = 62
5 mNow body moves with  25 m/s and travel the distance in 4 ss2 = 25×4 = 100 mNOw body comes to rest in 5 sv = u + at0 = 25 + a(5)a = - 5 m/s2Distance travelleds3 = ut + 12at2= 25×5 - 12×5×5×5= 62
5 mTotal distace travelled = 62 5+100+62
5 = 225 m