a body weighs 700N in air and 500N when completely immersed in water. Find the buoyant force acting on the body and relative density of the body

Dear Student,

$$\begin{gathered} \mathrm{Weight} \mathrm{of} \mathrm{body} \mathrm{in} \mathrm{air}, {\mathrm{W}}_1=700 \mathrm{N} \\ \mathrm{Weight} \mathrm{of} \mathrm{body} \mathrm{in} \mathrm{water}, {\mathrm{W}}_2=500 \mathrm{N} \\ \mathrm{Loss} \mathrm{of} \mathrm{weight}, \mathrm{W}={\mathrm{W}}_1-{\mathrm{W}}_2 \\ \mathrm{W}=700-500=200 \mathrm{N} \\ \mathrm{So} \mathrm{buoyant} \mathrm{force}, \mathrm{F}=\mathrm{Loss} \mathrm{of} \mathrm{weight} \\ \mathrm{F}=200 \mathrm{N} \end{gathered}$$

Relative density is the ratio of the density of a substance to the density of a given reference material. If density of substance is given then you can find the relative density.

Regards