a bomb of mass 6 kg initially at rest explodes into two fragments of masses 4 kg and 2 kg respectvely. if the greater mass moves with 5 m/s, the speed of 2 kg mass will be

5m/s

10m/s

15m/s

20m/s???

and explain.....plzzzz help

emergency!!

the velocity will be same as the object is fired by the potential energy of bomb which is at rest and due to motion it sets same velocity

Ans- 10m/s

According to law of conservation of linear momentum,

Total momentum before reaction=Total momentum after reaction

So,mass of bomb, m=6kg   velocity of bomb, v=0m/s  mass of greater piece, m1=4kg  velocity of greater piece, v1=5m/s        mass of smaller piece, m2=2kg  velocity of smaller piece, v2=?

 m*v=m1*v1+m2*v2

6*0=4*5+2*v2

0=20+2*v2

2*v2=-20

v2=-20/2

v2= -10m/s (negative sign for opposite direction)

Hence, v2=10m/s

thanks shan121... but r u 100% sure about the answer u hav given???

Yes I am 200% sure

Yes I am 500% sure