A brown mouse is mated with two female black mice. When each female has produced several litters of young, the first female has had 48 black and the second female has had 14 black and 11 brown young. Deduce the pattern of inheritance of coat color and the genotypes of all of the parents.( Black is the dominant trait).

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​Please find below the solution to the asked query     

​If black is the dominant coat colour, then it is represented by B (black) while the recessive allele is b (brown). Hence, brown male must be homozygous recessive (bb).

In the first cross between brown male and female, the female would be homozygous dominant(BB) and all offsprings will have a genotype Bb (heterozygous). This genotype produces all (48) black offsprings.

In the second cross between brown male and female, the female will be heterozygous (Bb). Hence, half of the offsprings are black (Bb) and half are brown (bb).
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