a bullet of mass 20g is to pass 2 points 30m apart in 4s .Find its kinetic energy

v = 30/4 = 7.5ms
m = 20g = 0.02kg 
t = 4s 
so,
KE = 0.5 (m x v2)
​       =  28.125 joules
so the kinetic energy is 28.125 joules
 
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Hope it helps! Regards..>>SUBHAJIT

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0.5625 J
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Solution

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v = 30/4 = 7.5 m/s
m = 20 g = 0.02 kg
t = 4s
K.E = 0.5 (m x v^2)
= 28.125 joules
 
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