Login

A bus of mass 10,000 Kg is moving with a velocity of 60 Km/h. Calculate the work done to stop
this bus.

mass of the bus = 10,000 Kg 
velocity = 60 Km/h = 16.67 m/s
work required to stop the car = change in kinetic energy
therefore, work done= final kinetic energy - initial kinetic energy
= 1/2mv2 - 1/2mu2
=1/2 * 10,000*(0)2 - 1/2 * 10,000 * (16.67)2
= 1/2 * 10,000 [ (0)2 - (16.67)2]
= 1/2 * 10,000 * 277.8889
= 1,389,444.5kJ
  • 13
View Full Answer
If this has helped you then don't forget to like !!!
  • -3
same as the above one
  • -1
4.5×100009
  • -4

Mass of the bus is 10,000 kg

Velocity = 60 km/h = (60 x 1000) m/hr = 60,000/3600 m/s = (50/3) m/s

Now work done = change in kinetic energy

Here, initial kinetic energy (in joule)

= (1/2).m.v²

= (1/2) x 10000 x (50/3)²

= 1,388,888.889

As the bus stops finally the final velocity is zero,

thus its final kinetic energy will be also 0 [ (1/2) x 10000 x 0 = 0 ]

Therefore, net work done

= initial KE - Final KE

= 1,388,888.889 - 0

= 1,388,888.889 J

  • 0
LIKE IF U UNDERSTOOD!!!
 
  • 1
What are you looking for?