A car accelerates uniformly from 18 km/hr to 36km/hr in 5s. Calculate, (I) the acceleration and (ii) the distance traveled by car in that time.

Dear student,
here,

u = 18 km/hr = 18 x 5/18 m/s = 5 m/s

v = 36 km/hr = 10 m/s

so, acceleration a = (v - u) / t = (10-5) / 5 = 1 m/s²

now, the total distance travelled will be

s = ut + (1/2)at²

or

s = 5x5+ (1/2)1.(5)²

or

s = 25+ 12.5

thus,

s = 37.5m
Regards.