A car of mass m is driven with acceleration a along a straight level road against a constant external resistance force R.When the velocity of the car is v,why is the rate at which the engine of the car is doing the work (R+ma)v Share with your friends Share 8 Siddhant Datta answered this 08 -28 View Full Answer Ameya Raj answered this Force required to oppose the resistive force R and moves with acceleration R+ma. Power=F*V (R+ma)V 1 Rashmi Prava Nayak answered this Rate of work done =force×displacement /time =force ×velocity. Total force =R+ma Therefore rate of work done =(R+ma) V. 1 Adarsh answered this P=(R+MA)V 40
