A car of mass m is driven with acceleration a along a straight level road against a constant external resistance force R.When the velocity of the car is v,why is the rate at which the engine of the car is doing the work (R+ma)v

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Force required to oppose the resistive force R and moves with acceleration R+ma.
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Rate of work done =force×displacement /time =force ×velocity. Total force =R+ma Therefore rate of work done =(R+ma) V.
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