A certain sum of money at compound interest becames Rs7,396 in 2 years and Rs7950.70 in 3 years.Find the rate of interest.

Here, use the copound interest formula,
A=P1+rnnt  ...(1)
Where,
P = principal amount (the initial amount you borrow or deposit)
r = annual rate of interest (as a decimal)
t = number of years the amount is deposited or borrowed for.
A= amount of money accumulated after n years, including interest.
n =  number of times, the interest is compounded per year 

 
Now, for the given question,
Let the principal be x and rate of interest be y
So, when the money is deposited for 2 years,
A = Rs 7396
t = 2 years
n = 1
Substituting the above values in equation (1), we get
7396=x1+y1127396=x1+y2                                ...(2)

Next, when the money is deposited for 3 years,
A = Rs 7950.70
t = 3 years
n = 1
Substituting the above values in equation (1), we get
7950.70=x1+y1137950.70=x1+y3                                ...(3)

Divide equation (3) by equation (2). So, we get
7950.707396=x1+y3x1+y21.075=1+yy=1.075-1y=0.075 

Therefore, the rate of interest is 0.075

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