A charge particle of charge Q,mass m is initially at rest at origin.Electric field is given by E along y axiswhile magnetic field is B along z axis. Find speed of particale when the coordinator of particale are (2 x 3.14mv/qB,0,0). Share with your friends Share 3 Parth answered this Zero -22 View Full Answer Nikhil Rana Y answered this Why zero reason 2 Bala answered this Radius R(R is maximum x distance)=mv/qB But given (6.28mv/qB,0,0)..so particle won't reach there So velocity zero -9 Ankit Singla answered this Checkout Attachment -19