# a circular flower bed is surrounded by a path 4m wide. the diameter of the flower bed is 66m. what is the area of the path?

• 2

Given that:-

Diameter of the flower bed(d) = 66 m

∴ Radius of the flower bed (r1) = 33 m

So, the area of the flower bed (A1) = πr12

= 3.14 × 33 × 33

= 3419.46 m2

Also the width of road is 4 m

∴ Radius of the flower bed with road (r2) = (33 + 4) m

= 37 m

So the area of the flower bed with road (A2) = πr22

= 3.14 × 37 × 37

= 4298.66 m2

Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)

= A2 – A1

= 4298.66 × 3419.46 m2

= 879.20 m2

• 3

Given that:-

Diameter of the flower bed(d) = 66 m

∴ Radius of the flower bed (r 1) = 33 m

So, the area of the flower bed (A1) = πr 1 2

= 3.14 x 33 x 33

= 3419.46 m2

Also the width of road is 4 m

∴ Radius of the flower bed with road (r 2) = (33 + 4) m

= 37 m

So the area of the flower bed with road (A2) = πr2 2

= 3.14 x 37 x 37

= 4298.66 m2

Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)

= A2 – A1

= 4298.66 - 3419.46 m2

= 879.20 m2

• 13
Radius of the flower bed= 66m

total area - area of garden = area of path
(22/7)*70*70- (22/7) * 66 * 66
=1709.7 m^2
• -1

Abhijeet you did it wrong. First we must take out the radius and then add the width of the path in it.

I was going to answer this question but i found @ayushi did it correctly.....

Thumbs up to you ayushi..

• 3

Diameter of flower bed =  66m.

So, area of flower bed = 22/7 x 33 x 33 = 23958/7 or 3422 4/7 m.sq.

Diameter of flower bed including path = 66 + 2(4) = 74 m