A circulr coil of 50 turns and radius 0.2 m carries a current of 12 ampere. Find the magnetic field at the centre of the coil. Share with your friends Share 1 Vara answered this Magnetic field at the centre of the circular coil:B=μo2nIr =4π×10-72×50×120.2 =1.88×10-3 T 4 View Full Answer Sakshi Jha answered this b=magnetic field nd N=no. of turns I=CURRENT nd r =radius so, B =(Uo/4pie)×2pieNI/r nd Uo/4pie=10^-7 after solving it will b 1777.7×10^-7 1
