A Concave mirror forms an erect Image of an object placed at a distance of 10 cm from it if the image is twice as large as the object where it is formed find the focal length
Dear Student,
The mirror produces two times enlarged image.
So, magnification(m) = 2
WE KNOW, magnification of spherical mirrors = m = -v/u
Where v is the distance between image and mirror and u is the distance between object and mirror.
Here, u = -10 cm
=> 2 = -V/-10
=>v = 30
So , the distance between image and mirror = 20 cm
1/v + 1/u = 1/f(mirror formula)
1/20 + 1/-10 = 1/f
1/20 - 1/10 = 1/f
-1/10 = 1/f
f = -10 cm
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
The mirror produces two times enlarged image.
So, magnification(m) = 2
WE KNOW, magnification of spherical mirrors = m = -v/u
Where v is the distance between image and mirror and u is the distance between object and mirror.
Here, u = -10 cm
=> 2 = -V/-10
=>v = 30
So , the distance between image and mirror = 20 cm
1/v + 1/u = 1/f(mirror formula)
1/20 + 1/-10 = 1/f
1/20 - 1/10 = 1/f
-1/10 = 1/f
f = -10 cm
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
