A cricket ball of mass 0.4 kg moving with a velocity of 72 m/s is bought to rest by a player . What is the magnitude of the average force exerted by the player ?

Given, m = 0.4 kg
u = 72 m/s
v = 0 m/s
​Let t is the time in which ball is brought to rest.
Impulse = Change in momentum = m (v - u) = 0.4 X (0 - 72) = - 28.8 Ns
​As impulse = Force X time 
Force = $\frac{Impulse }{time} = \frac{-28.8}{t} N$