a cricket ball of mass 70g moving with a velocity of 0.5m/s is stopped by a player in 0.5s . what is the force applied by the player to stop the ball
@tanvi: Slight error.
mass of the ball= 70 g = 0.07 kg
u= 0.5 m s
v= 0
t= 0.5 sec
f=ma= m (v-u/t) = 0.07 (-0.5/0.5) = -0.07 N