A CURRENT OF 5 A IS FLOWING THROUGH A 10 TURN CIRCULAR COIL OF RADIUS 7 cm THE COIL IS IN X - YPLANE. WHAT IS ITS MAGNETIC DIPOLE MOMENT ?IF THIS COIL WERE TO BE PLACED IN A UNIFORM EXTERNAL MAGNETIC FIELD DIRECTED ALONG XAXIS IN WHICH PLANE WILL THE COIL LIE WHEN IN EQUILIBRIUM Share with your friends Share 3 Ved Prakash Lakhera answered this Dipole moment = nIA = 10×5×πr2 = 50×227×7×7×10-4 = 350×22×10-4 = 0.77ampere metre2.The torque experienced by currentof 5A carrying circular coil of radius 7cm having 10 number of turnsis given by,Torque (τ) = nIA→×B→ = 0.77×B→.As the area vector is working along Z axis and magnetic field is directed along X axis ,so the force on the coil will act alongY axis and the coil will lie in YZ plane. 8 View Full Answer
