A decimal number is of the form 3 b .0276, where b represents a digit. The decimal is then written in the form of the simplest fraction. The prime factorisation of the denominator of the fraction is 2 2 × 5 4 × 7 x , where x is a non-negative integer.

It is known that a rational number p/q has a terminating decimal expansion, if can be prime factorised in the form 2n5m, where and m are non-negative integers.

Therefore, prime factorisation of the denominator of the simplest fraction equivalent to the number 3b.0276 is of the form 2n5m, where and m are non-negative integers.



It is given that prime factorisation of the denominator of the simplest equivalent fraction is 2^2 x 5^4 x 7^x

∴ 2n5= 22 x 54 x 7x

⇒ 7= 1

⇒ x = 0

Thus, the value of is 0. 

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 What we have to find , please tell?

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