A dipole of length 0.1 m consists of two charges of + 500 µC. What is its electric dipole moment? Calculate the electric field due to the dipole at a point on the axis distant 0.2 m from the centre of the dipole.

Dear Student,
Electric dipole moment, p = 2ql, where, q= magnitude of either of the charge=500μC and 2l is the distance between the dipoles = 0.1mp = 500×10-6×0.1 =50×10-6 C-mElectric field due to a dipole of length 2l having a dipole moment p at a point which is at r=0.2m away from its centre and is on its axis:E = 14πεo2prr2-l22 = 9×1092×50×10-6×0.2(0.04 - 0.014)2=112.5×106 V/mRegards

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