a double convex lens made of glass of refractive index 1.5 has its both surfaces of equal radii of curvature of 20 cm each an object of 5 height is placed at a distance of 10 cm from the lens .find the position ,nature and size of the image
u = -10 cm r =20 cm so f = 10 cm
so acc. to lens formula - 1 /u + 1 /v =1 /f
Put the value of u and f
1 /v =- 1 /10 -1 / 10
v = -5
Position of image =-5 cm
since it is negative the image is formed on the same side of the lens and is virtual
size =magnified